Attempting to draw an incredible circle (bended) that goes between Australia, Baja California, Long Island, and Sweden.

At that point, he expresses that two of planes rainbows inside three hours of each other, one over Baja and one over Sweden. He guarantees these are on inverse sides of the Earth, in spite of the fact that they are really 10,000 km or a fourth of an outline separated. Anyway, he utilizes this to infer that the orbital time of the satellite must be six hours.

Those of you acquainted with the ISS realize that it is 400 kilometers up and circles in around an hour and a half. Those of you likewise acquainted with orbital elements realize that a progressively removed circle takes longer, so you could presume that the moon ought to be higher up than the ISS. You can utilize Kepler’s or Newton’s Laws to make sense of how high a six hour circle around the Earth would be:

T2=(R+h)34πGM

This ought to be around 18,000 km if my figurings are right. In the story, every one of the planes vanish when attempting to break the height record, and this occurs at forty miles (70 km) elevation. A slight think little of given the anticipated orbital period, yet lucky for motivations behind the story.

How might this planet look from Earth? In the story, a character asks how this moon could exist if no one has ever observed it. The hero recommends that it must move so quick that no one could ever figure out how to witness it, similar to the shot from a rifle. How about we check whether this holds up. Above all else, we can figure the speed dependent on the stature and period, it’s simply 2π (6380 km + 40 miles)/6 hours=1.8 km/s.